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4x^2-6x-0.01=0
a = 4; b = -6; c = -0.01;
Δ = b2-4ac
Δ = -62-4·4·(-0.01)
Δ = 36.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-\sqrt{36.16}}{2*4}=\frac{6-\sqrt{36.16}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+\sqrt{36.16}}{2*4}=\frac{6+\sqrt{36.16}}{8} $
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